sommets 25x^2+4y^2+100x-40y=400

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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vertices 25x²+4y²+100x−40y=400

Solution

(−2, 5+5√6), (−2, 5−5√6)

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Ellipse vertices

The vertices are the two points on the ellipse that intersect the major axis
For an ellipse with major axis parallel to the y-axis, the vertices are (h, k+b), (h, k−b)

(h, k+b), (h, k−b)

Calculate ellipse properties

25x²+4y²+100x−40y=400: Ellipse with center (h, k)=(−2, 5), b=5√6, a=2√6

(−2, 5+5√6), (−2, 5−5√6)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

sommets 25x^2+4y^2+100x-40y=400

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