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symmetry t2
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Solution
t=0
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Axis of Symmetry
For a parabola in standard form y=ax2+bx+cthe axis of symmetry is the vertical line that goes through the vertex x=−b2a
Axis of Symmetry for y=ax2+bx+cis x=−b2a a=1,b=0
t=−02·1
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t=0
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Hey there, we're really sorry but we couldn't get the graph to work out