variância {0.42, 0.52, 0.58, 0.62}

Topic

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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variance 0.42, 0.52, 0.58, 0.62

Solution

0.00756…

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Solution steps

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Sample Variance

The sample variance measures how much the data is spread out in the sample.
For a data set x₁, … , x_n (n elements) with an average ̅ x, Var(X)=∑_i=1ⁿ(x_i−̅ x)²n−1

Compute the average, ̅ x: 0.535

Compute ∑_i=1ⁿ(x_i−̅ x)²: 0.0227

Compute the number of terms in the data set: n=4

Compute Var(X)=∑_i=1ⁿ(x_i−̅ x)²n−1 : 0.00756…

0.00756…

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

variância {0.42, 0.52, 0.58, 0.62}

Solution

Solution steps

Number Line