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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

vertex (x+3)^2=-20(y-1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

π

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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quadrant (−2, 3)

Solution

Quadrant II

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(−2, 3)

Cartesian quadrants

In the Cartesian coordinate system, the four quadrants are defined as follows:
Quadrant I - (top right): Both x and y coordinates are positive.
Quadrant II - (top left): x is negative and y is positive.
Quadrant III - (bottom left): Both x and y coordinates are negative.
Quadrant IV - (bottom right): x is positive and y is negative.

Check point coordinates according to quadrant's definition

x=−2 is negative
y=3 is positive

Quadrant II

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