vertices |3-(3x^2)/(49)|

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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vertices |3−3x²49 |

Solution

(−7, 0), (7, 0)

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Absolute value function vertex definition

Absolute value function vertex points are points where absolute values are zeros

Find the absolute values zeroes:

Solve |3−3x²49 |=0: x=−7, x=7

x=−7, x=7

Plug in x=−7 to find the y value: (−7, 0)

Plug in x=7 to find the y value: (7, 0)

Therefore absolute value function vertices are

(−7, 0), (7, 0)

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domain |3−3x²49 |

range |3−3x²49 |

intercepts |3−3x²49 |

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertices |3-(3x^2)/(49)|

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