y = 2x+1

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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y=2x+1

Solution

X Intercepts: (−12 , 0), Y Intercepts: (0, 1)

Slope: m=2

Inverse: x−12

Domain: −∞ <x<∞

Range: −∞ <f(x)<∞

Interval Notation

Domain: (−∞ , ∞ )

Range: (−∞ , ∞ )

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Axis interception points of 2x+1: X Intercepts: (−12 , 0), Y Intercepts: (0, 1)

Slope of 2x+1: m=2

Inverse of 2x+1: x−12

Domain of 2x+1 : −∞ <x<∞

Range of 2x+1: −∞ <f(x)<∞

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ddx (2x+1)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

y = 2x+1

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