derivative of (2x-5e^x)

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z²6 −5z2 −9=0

Solution

z=18, z=−3

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Solve by:

Quadratic formula

Completing the square

Factoring method

One step at a time

z²6 −5z2 −9=0

Find Least Common Multiplier of 6, 2: 6

Multiply by LCM=6

z²6 · 6−5z2 · 6−9· 6=0· 6

Simplify

z²−15z−54=0

Solve with the quadratic formula

z_{1, 2}=−(−15)± √(−15)²−4· 1· (−54)2· 1

√(−15)²−4· 1· (−54)=21

z_{1, 2}=−(−15)± 212· 1

Separate the solutions

z₁=−(−15)+212· 1 , z₂=−(−15)−212· 1

z=−(−15)+212· 1 : 18

z=−(−15)−212· 1 : −3

The solutions to the quadratic equation are:

z=18, z=−3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (2x-5e^x)

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