Solving Equations That Contain Fractions Using the Multiplication Property of Equality
Learning Outcomes
- Use the multiplication and division properties to solve equations with fractions and division
Solve Equations with Fractions Using the Multiplication and Division Properties of Equality
We will solve equations that require multiplication or division to isolate the variable. First, let's consider the division property of equality again.
The Division Property of Equality
For any numbers
a,b, and
c,
if a=b, then ca=cb.
If you divide both sides of an equation by the same quantity, you still have equality.
Let's put this idea in practice with an example. We are looking for the number you multiply by 10 to get 44, and we can use division to find out.
Example
Solve:
10q=44
Solution:
|
10q=44 |
Divide both sides by 10 to undo the multiplication. |
1010q=1044 |
Simplify. |
q=522 |
Check: |
|
Substitute q=522 into the original equation. |
10(522)=?44 |
|
Simplify. |
)102()522)=?44 |
|
Multiply. |
44=44✓ |
|
The solution to the equation was the fraction
522. We leave it as an improper fraction.
Try It
[ohm_question]146141[/ohm_question]
Now, consider the equation 4x=3. We want to know what number divided by 4 gives 3. So to "undo" the division, we will need to multiply by 4. The Multiplication Property of Equality will allow us to do this. This property says that if we start with two equal quantities and multiply both by the same number, the results are equal.
The Multiplication Property of Equality
For any numbers
a,b, and
c,
if a=b, then ac=bc.
If you multiply both sides of an equation by the same quantity, you still have equality.
Let’s use the Multiplication Property of Equality to solve the equation 7x=−9.
Example
Solve:
7x=−9.
Answer:
Solution:
|
7x=−9 |
Use the Multiplication Property of Equality to multiply both sides by 7 . This will isolate the variable. |
7⋅7x=7(−9) |
Multiply. |
77x=−63 |
Simplify. |
x=−63 |
Check.
Substitute −63 for x in the original equation. |
7−63=?−9 |
|
The equation is true. |
−9=−9✓ |
|
Try It
[ohm_question]146147[/ohm_question]
Example
Solve:
−8p=−40
Answer:
Solution:
Here, p is divided by −8. We must multiply by −8 to isolate p.
|
−8p=−40 |
Multiply both sides by −8 |
−8(−8p)=−8(−40) |
Multiply. |
−8−8p=320 |
Simplify. |
p=320 |
Check: |
|
|
Substitute p=320 . |
−8320=?−40 |
|
The equation is true. |
−40=−40✓ |
|
Try It
[ohm_question]146336[/ohm_question]
In the following video we show two more examples of when to use the multiplication and division properties to solve a one-step equation.
https://youtu.be/BN7iVWWl2y0
Solve Equations with a Coefficient of −1
Look at the equation −y=15. Does it look as if y is already isolated? But there is a negative sign in front of y, so it is not isolated.
There are three different ways to isolate the variable in this type of equation. We will show all three ways in the next example.
Example
Solve:
−y=15
Answer:
Solution:
One way to solve the equation is to rewrite −y as −1y, and then use the Division Property of Equality to isolate y.
|
−y=15 |
Rewrite −y as −1y . |
−1y=15 |
Divide both sides by −1. |
−1−1y=−115 |
Simplify each side. |
y=−15 |
Another way to solve this equation is to multiply both sides of the equation by
−1.
|
y=15 |
Multiply both sides by −1. |
−1(−y)=−1(15) |
Simplify each side. |
y=−15 |
The third way to solve the equation is to read
−y as "the opposite of
y." What number has
15 as its opposite? The opposite of
15 is
−15. So
y=−15.
For all three methods, we isolated
y is isolated and solved the equation.
Check:
|
y=15 |
Substitute y=−15 . |
−(−15)=?(15) |
Simplify. The equation is true. |
15=15✓ |
Try It
[ohm_question]146153[/ohm_question]
In the next video we show more examples of how to solve an equation with a negative variable.
https://youtu.be/FJmNpHeOcpo
Solve Equations with a Fraction Coefficient
When we have an equation with a fraction coefficient we can use the Multiplication Property of Equality to make the coefficient equal to 1.
For example, in the equation:
43x=24
The coefficient of x is 43. To solve for x, we need its coefficient to be 1. Since the product of a number and its reciprocal is 1, our strategy here will be to isolate x by multiplying by the reciprocal of 43. We will do this in the next example.
Example
Solve:
43x=24
Answer:
Solution:
|
43x=24 |
Multiply both sides by the reciprocal of the coefficient. |
34⋅43x=34⋅24 |
Simplify. |
1x=34⋅124 |
Multiply. |
x=32 |
Check: |
43x=24 |
|
Substitute x=32 . |
43⋅32=?24 |
|
Rewrite 32 as a fraction. |
43⋅132=?24 |
|
Multiply. The equation is true. |
24=24✓ |
|
Notice that in the equation
43x=24, we could have divided both sides by
43 to get
x by itself. Dividing is the same as multiplying by the reciprocal, so we would get the same result. But most people agree that multiplying by the reciprocal is easier.
Try It
[ohm_question]146156[/ohm_question]
Example
Solve:
−83w=72
Answer:
Solution:
The coefficient is a negative fraction. Remember that a number and its reciprocal have the same sign, so the reciprocal of the coefficient must also be negative.
|
83w=72 |
Multiply both sides by the reciprocal of −83 . |
−38(−83w)=(−38)72 |
Simplify; reciprocals multiply to one. |
1w=−38⋅172 |
Multiply. |
w=−192 |
Check: |
−83w=72 |
|
Let w=−192 . |
−83(−192)=?72 |
|
Multiply. It checks. |
72=72✓ |
|
Try It
[ohm_question]146158[/ohm_question]
In the next video example you will see another example of how to use the reciprocal of a fractional coefficient to solve an equation.
https://youtu.be/Ea5eW8rZxEILicenses & Attributions
CC licensed content, Original
- Solving One Step Equations Using Multiplication and Division (Basic). Authored by: James Sousa (Mathispower4u.com) for Lumen Learning. License: CC BY: Attribution.
CC licensed content, Shared previously
- Ex: Solving One Step Equation in the Form: -x = a. Authored by: James Sousa (Mathispower4u.com). License: CC BY: Attribution.
- Ex: Solve a One Step Equation by Multiplying by Reciprocal (a/b)x=-c. Authored by: James Sousa (Mathispower4u.com). License: CC BY: Attribution.
- Question ID: 146141, 146147, 146336, 146153, 146156, 146158. Authored by: Alyson Day. License: CC BY: Attribution. License terms: IMathAS Community License CC- BY + GPL.
CC licensed content, Specific attribution
- Prealgebra. Provided by: OpenStax License: CC BY: Attribution. License terms: Download for free at http://cnx.org/contents/caa57dab-41c7-455e-bd6f-f443cda5519c@9.757.