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Study Guides > ALGEBRA / TRIG I

Translating and Solving Word Problems and Applications

Learning Outcomes

  • Translate word phrases to equations and solve
  • Translate and solve applications
In previous chapters, we translated word phrases into equations. This skill will help you when you solve word problems. Previously, you translated phrases into expressions, and now we will translate phrases into mathematical equations so we can solve them.  But before we get started, let's define some important terminology:
  • variables:  Variables are symbols that stand for an unknown quantity, often represented with letters, like [latex]x, y[/latex], or [latex]z[/latex].
  • coefficient: Sometimes a variable is multiplied by a number. This number is called the coefficient of the variable. For example, the coefficient of [latex]3x[/latex] is [latex]3[/latex].
  • term: A single number, or variables and numbers connected by multiplication. For example, [latex]-4, 6x[/latex], and [latex]x^2[/latex] are all terms.
  • expression: Groups of terms connected by addition and subtraction. For example, [latex]2x^2-5[/latex] is an expression.
  • equation:  An equation is a mathematical statement that two expressions are equal. An equation will always contain an equal sign with an expression on each side. Think of an equal sign as meaning "the same as". Some examples of equations are [latex]y = mx +b[/latex],  [latex]\frac{3}{4}r = v^{3} - r[/latex], and  [latex]2(6-d) + f(3 +k) = \frac{1}{4}d[/latex] .
The following figure shows how coefficients, variables, terms, and expressions all come together to make equations. In the equation [latex]2x-3^2=10x[/latex], the variable is [latex]x[/latex], a coefficient is [latex]10[/latex], a term is [latex]10x[/latex], and an expression is [latex]2x-3^2[/latex].
Equation made of coefficients, variables, terms, and expressions. Equation made of coefficients, variables, terms, and expressions.

Translate Phrases into Equations

The first step in translating phrases into equations is to look for the word (or words) that translate(s) to the equal sign. The table below reminds us of some of the words that translate to the equal sign.
Equals (=)
is is equal to is the same as the result is gives was will be
Let’s review the steps we used to translate a sentence into an equation.
Translate a word sentence to an algebraic equation.
  1. Locate the "equals" word(s). Translate to an equal sign.
  2. Translate the words to the left of the "equals" word(s) into an algebraic expression.
  3. Translate the words to the right of the "equals" word(s) into an algebraic expression.
In our first example, we will translate and solve a one-step equation.

Example

Translate and solve: five more than [latex]x[/latex] is equal to [latex]26[/latex]. Solution:
Translate. Five more than [latex]x[/latex]   [latex]\Rightarrow\quad{x+5}[/latex]is equal to   [latex]\Rightarrow\quad{=}[/latex] [latex-display]26[/latex]   [latex]\Rightarrow\quad{26}[/latex-display] [latex]x+5=26[/latex]
Subtract 5 from both sides. [latex]x+5\color{red}{-5}=26\color{red}{-5}[/latex]
Simplify. [latex]x=21[/latex]
Check:Is [latex]26[/latex] five more than [latex]21[/latex] ? [latex-display]21+5\stackrel{\text{?}}{=}26[/latex-display] [latex-display]26=26\quad\checkmark[/latex-display] The solution checks.
 

TRY IT

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Example

Translate and solve: The difference of [latex]5p[/latex] and [latex]4p[/latex] is [latex]23[/latex].

Answer:

Solution:
Translate. The difference of [latex]5p[/latex] and [latex]4p[/latex]   [latex]\Rightarrow\quad{5p-4p}[/latex]is   [latex]\Rightarrow\quad{=}[/latex] [latex-display]23[/latex]   [latex]\Rightarrow\quad{23}[/latex-display] [latex]5p-4p=23[/latex]
Simplify. [latex]p=23[/latex]
Check:[latex]5p-4p=23[/latex] [latex-display]5(23)-4(23)\stackrel{?}{=}23[/latex-display] [latex-display]115-92\stackrel{?}{=}23[/latex-display] [latex]23=23\quad\checkmark[/latex]
The solution checks.

 

TRY it

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Watch this video for more examples of how to translate a phrase into an equation, then solve it. https://youtu.be/w-64WyZYAMU

Translate and Solve Applications

In most of the application problems we solved earlier, we were able to find the quantity we were looking for by simplifying an algebraic expression. Now we will be using equations to solve application problems. We’ll start by restating the problem in just one sentence, then we'll assign a variable, and then we'll translate the sentence into an equation to solve. When assigning a variable, choose a letter that reminds you of what you are looking for.

Example

The Robles family has two dogs, Buster and Chandler. Together, they weigh [latex]71[/latex] pounds. Chandler weighs [latex]28[/latex] pounds. How much does Buster weigh?

Answer:

Solution:
Read the problem carefully.
Identify what you are asked to find, and choose a variable to represent it. How much does Buster weigh?Let [latex]b=[/latex] Buster's weight
Write a sentence that gives the information to find it. Buster's weight plus Chandler's weight equals 71 pounds.
We will restate the problem, and then include the given information. Buster's weight plus 28 equals 71.
Translate the sentence into an equation, using the variable [latex]b[/latex]. [latex]b+28=71[/latex]
Solve the equation using good algebraic techniques. [latex]b+28-28=71-28[/latex][latex]b=43[/latex]
Check the answer in the problem and make sure it makes sense.
Is 43 pounds a reasonable weight for a dog?  Yes.
Does Buster's weight plus Chandler's weight equal 71 pounds?  [latex]43+28\stackrel{?}{=}71[/latex]
 [latex]71=71\quad\checkmark[/latex]
Write a complete sentence that answers the question, "How much does Buster weigh?" Buster weighs [latex]43[/latex] pounds.

 

try it

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Devise a problem-solving strategy.

  1. Read the problem. Make sure you understand all the words and ideas.
  2. Identify what you are looking for.
  3. Name what you are looking for. Choose a variable to represent that quantity.
  4. Translate into an equation. It may be helpful to restate the problem in one sentence with all the important information. Then, translate the English sentence into an algebra equation.
  5. Solve the equation using good algebra techniques.
  6. Check the answer in the problem and make sure it makes sense.
  7. Answer the question with a complete sentence.
Let's take a look at the problem-solving strategy in action.

example

Shayla paid $[latex]24,575[/latex] for her new car. This was $[latex]875[/latex] less than the sticker price. What was the sticker price of the car?

Answer:

Solution:
What are you asked to find? "What was the sticker price of the car?"
Assign a variable. Let [latex]s=[/latex] the sticker price of the car.
Write a sentence that gives the information to find it. $24,575 is $875 less than the sticker price.$24,575 is $875 less than [latex]s[/latex].
Translate into an equation. [latex]24,575=s-875[/latex]
Solve. [latex]24,575+875=s-875+875[/latex][latex]24,575=s[/latex]
Check: Is $875 less than $25,450 equal to $24,575?[latex]25,450 - 875\stackrel{?}{=}24,575[/latex] [latex]24,575=24,575\quad\checkmark[/latex]
Write a sentence that answers the question. The sticker price was $[latex]25,450[/latex].

Now you can try translating an equation from a statement that represents subtraction.

try it

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In the following video, you will see another example of how to translate a phrase into an equation and solve. https://youtu.be/0eUNh_Qkw9A

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Licenses & Attributions

CC licensed content, Original

  • One Step Linear Equation in One Variable App: Sticker Price. Authored by: James Sousa (Mathispower4u.com) for Lumen Learning. License: CC BY: Attribution.
  • Question Id 145529, 145530, 141742, 141743, 141746. Authored by: Lumen Learning. License: CC BY: Attribution. License terms: IMathAS Community License, CC-BY + GPL.

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