Solving Inequalities
Learning Outcomes
- Solve single-step inequalities
- Solve multi-step inequalities
Multiplication and Division Properties of Inequality
Solving inequalities is very similar to solving equations, except you have to reverse the inequality symbols when you multiply or divide both sides of an inequality by a negative number. There are three ways to represent solutions to inequalities: an interval, a graph, and an inequality. Because there is usually more than one solution to an inequality, when you check your answer, you should check the end point and one other value to check the direction of the inequality. When we work with inequalities, we can usually treat them similar to but not exactly as we treat equations. We can use the addition property and the multiplication property to help us solve them. The one exception is when we multiply or divide by a negative number; doing so reverses the inequality symbol. The following table illustrates how the multiplication property is applied to inequalities, and how multiplication by a negative reverses the inequality:Start With | Multiply By | Final Inequality |
[latex]a>b[/latex] | [latex]c[/latex] | [latex]ac>bc[/latex] |
[latex]5>3[/latex] | [latex]3[/latex] | [latex]15>9[/latex] |
[latex]a>b[/latex] | [latex]-c[/latex] | [latex]-ac<-bc[/latex] |
[latex]5>3[/latex] | [latex]-3[/latex] | [latex]-15<-9[/latex] |
Start With | Divide By | Final Inequality |
[latex]a>b[/latex] | [latex]c[/latex] | [latex] \displaystyle \frac{a}{c}>\frac{b}{c}[/latex] |
[latex]4>2[/latex] | [latex]2[/latex] | [latex] \displaystyle \frac{4}{2}>\frac{2}{2}[/latex] |
[latex]a>b[/latex] | [latex]-c[/latex] | [latex] \displaystyle -\frac{a}{c}<-\frac{b}{c}[/latex] |
[latex]4>2[/latex] | [latex]-2[/latex] | [latex] \displaystyle -\frac{4}{2}<-\frac{2}{2}[/latex] |
Example
Illustrate the multiplication property for inequalities by solving each of the following:- [latex]3x<6[/latex]
- [latex]-2x - 1\ge 5[/latex]
- [latex]5-x>10[/latex]
Answer: a. [latex-display]\begin{array}{cc}\hfill3x<6 \hfill\\\dfrac{1}{3}\normalsize\left(3x\right)<\left(6\right)\dfrac{1}{3} \\ \hfill{x}<2 \hfill\end{array}[/latex-display] b. [latex-display]\begin{array}{rr}-2x - 1\ge 5\\ \hfill\hfill-2x\ge 6\end{array}[/latex-display] Multiply both sides by [latex]-\dfrac{1}{2}[/latex]. [latex-display]\begin{array}{ll}\hfill\hfill\left(-\dfrac{1}{2}\normalsize\right)\left(-2x\right)\ge \left(6\right)\left(-\dfrac{1}{2}\normalsize\right)\end{array}[/latex-display] Reverse the inequality. [latex-display]\begin{array}{l}\hfill&\hfill&\hfill&\hfill&\hfill x\le -3\end{array}[/latex-display] c. [latex-display]\begin{array}{ll}5-x>10\\ -x>5\hfill &\hfill\end{array}[/latex-display] Multiply both sides by [latex] -1[/latex]. [latex-display]\left(-1\right)\left(-x\right)>\left(5\right)\left(-1\right)[/latex-display] Reverse the inequality [latex-display]x<-5[/latex-display]
Solve Inequalities Using the Addition Property
When we solve equations, we may need to add or subtract in order to isolate the variable; the same is true for inequalities. There are no special behaviors to watch out for when using the addition property to solve inequalities. The following table illustrates how the addition property applies to inequalities.Start With | Add | Final Inequality |
[latex]a>b[/latex] | [latex]c[/latex] | [latex]a+c>b+c[/latex] |
[latex]5>3[/latex] | [latex]3[/latex] | [latex]8>6[/latex] |
[latex]a>b[/latex] | [latex]-c[/latex] | [latex]a-c>b-c[/latex] |
[latex]5>3[/latex] | [latex]-3[/latex] | [latex]2>0[/latex] |
Example
Illustrate the addition property for inequalities by solving each of the following:- [latex]x - 15<4[/latex]
- [latex]6\ge x - 1[/latex]
- [latex]x+7>9[/latex]
Answer: The addition property for inequalities states that if an inequality exists, adding or subtracting the same number on both sides does not change the inequality. a. [latex-display]\begin{array}{rr}\hfill x - 15<4\hfill\hfill \\ \hfill x - 15+15<4+15\hfill& \text{Add 15 to both sides.}\hfill\\\hfill\quad x<19 \hfill\end{array}[/latex-display] b. [latex-display]\begin{array}{rr}\hfill 6≥ x - 1\hfill\hfill \\\hfill 6+1\ge x - 1+1\hfill & \text{Add 1 to both sides}.\hfill \\\quad\quad 7≥ x\hfill \end{array}[/latex-display] c. [latex-display]\begin{array}{rr}\hfill x+7>9\hfill\hfill\\\hfill x+7 - 7>9 - 7\hfill & \text{Subtract 7 from both sides}.\hfill\quad \\\hfill x>2\hfill \end{array}[/latex-display]
Solve Multi-Step Inequalities
As the previous examples have shown, we can perform the same operations on both sides of an inequality, just as we do with equations. To isolate the variable and solve, we combine like terms and perform operations with the multiplication and addition properties.Example
Solve the inequality: [latex]13 - 7x\ge 10x - 4[/latex].Answer: Solving this inequality is similar to solving an equation up until the last step.
Try It
[ohm_question]143594[/ohm_question]Example
Solve the following inequality and write the answer in interval notation: [latex]-\dfrac{3}{4}\normalsize x\ge -\dfrac{5}{8}\normalsize +\dfrac{2}{3}\normalsize x[/latex].Answer: We begin solving in the same way we do when solving an equation.
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CC licensed content, Original
- Revision and Adaptation. Provided by: Lumen Learning License: CC BY: Attribution.
CC licensed content, Shared previously
- Unit 10: Solving Equations and Inequalities, from Developmental Math: An Open Program. Provided by: Monterey Institute of Technology and Education Located at: https://www.nroc.org/. License: CC BY: Attribution.
- Ex: Solving One Step Inequalities by Adding and Subtracting (Variable Left Side). Authored by: James Sousa (Mathispower4u.com) for Lumen Learning. License: CC BY: Attribution.
- Ex: Solving One Step Inequalities by Adding and Subtracting (Variable Right Side). Authored by: James Sousa (Mathispower4u.com) for Lumen Learning. License: CC BY: Attribution.
- Ex: Solve One Step Linear Inequality by Dividing (Variable Left). Authored by: James Sousa (Mathispower4u.com) for Lumen Learning. License: CC BY: Attribution.
- Ex: Solve One Step Linear Inequality by Dividing (Variable Right). Authored by: James Sousa (Mathispower4u.com) for Lumen Learning. License: CC BY: Attribution.