Rational Expressions
Learning Outcomes
- Simplify rational expressions.
- Multiply and divide rational expressions.
- Find the least common denominator of two rational expressions.
- Add and subtract rational expressions.
- Simplify complex rational expressions.
[latex]\frac{280+9x}{x}[/latex]
Notice that the result is a polynomial expression divided by a second polynomial expression. In this section, we will explore quotients of polynomial expressions.Simplifying Rational Expressions
The quotient of two polynomial expressions is called a rational expression. We can apply the properties of fractions to rational expressions such as simplifying the expressions by canceling common factors from the numerator and the denominator. To do this, we first need to factor both the numerator and denominator. Let’s start with the rational expression shown.[latex]\frac{{x}^{2}+8x+16}{{x}^{2}+11x+28}[/latex]
[latex-display]\\[/latex]We can factor the numerator and denominator to rewrite the expression as [latex]\frac{{\left(x+4\right)}^{2}}{\left(x+4\right)\left(x+7\right)}[/latex-display]How To: Given a rational expression, simplify it
- Factor the numerator and denominator.
- Cancel any common factors.
Example: Simplifying Rational Expressions
Simplify [latex]\frac{{x}^{2}-9}{{x}^{2}+4x+3}[/latex].Answer: [latex-display]\begin{array}{lllllllll}\frac{\left(x+3\right)\left(x - 3\right)}{\left(x+3\right)\left(x+1\right)}\hfill & \hfill & \hfill & \hfill & \text{Factor the numerator and the denominator}.\hfill \\ \frac{x - 3}{x+1}\hfill & \hfill & \hfill & \hfill & \text{Cancel common factor }\left(x+3\right).\hfill \end{array}[/latex-display]
Analysis of the Solution
We can cancel the common factor because any expression divided by itself is equal to 1.Q & A
Can the [latex]{x}^{2}[/latex] term be cancelled in the above example? No. A factor is an expression that is multiplied by another expression. The [latex]{x}^{2}[/latex] term is not a factor of the numerator or the denominator.Try It
Simplify [latex]\frac{x - 6}{{x}^{2}-36}[/latex].Answer: [latex]\frac{1}{x+6}[/latex]
Multiplying Rational Expressions
Multiplication of rational expressions works the same way as multiplication of any other fractions. We multiply the numerators to find the numerator of the product, and then multiply the denominators to find the denominator of the product. Before multiplying, it is helpful to factor the numerators and denominators just as we did when simplifying rational expressions. We are often able to simplify the product of rational expressions.How To: Given two rational expressions, multiply them
- Factor the numerator and denominator.
- Multiply the numerators.
- Multiply the denominators.
- Simplify.
Example: Multiplying Rational Expressions
Multiply the rational expressions and show the product in simplest form:Answer:
[latex]\begin{array}{cc}\frac{\left(x+5\right)\left(x - 1\right)}{3\left(x+6\right)}\cdot \frac{\left(2x - 1\right)}{\left(x+5\right)}\hfill & \text{Factor the numerator and denominator}.\hfill \\ \frac{\left(x+5\right)\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)\left(x+5\right)}\hfill & \text{Multiply numerators and denominators}.\hfill \\ \frac{\cancel{\left(x+5\right)}\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)\cancel{\left(x+5\right)}}\hfill & \text{Cancel common factors to simplify}.\hfill \\ \frac{\left(x - 1\right)\left(2x - 1\right)}{3\left(x+6\right)}\hfill & \hfill \end{array}[/latex]
Try It
Multiply the rational expressions and show the product in simplest form:Answer: [latex]\frac{\left(x+5\right)\left(x+6\right)}{\left(x+2\right)\left(x+4\right)}[/latex]
Dividing Rational Expressions
Division of rational expressions works the same way as division of other fractions. To divide a rational expression by another rational expression, multiply the first expression by the reciprocal of the second. Using this approach, we would rewrite [latex]\frac{1}{x}\div \frac{{x}^{2}}{3}[/latex] as the product [latex]\frac{1}{x}\cdot \frac{3}{{x}^{2}}[/latex]. Once the division expression has been rewritten as a multiplication expression, we can multiply as we did before.How To: Given two rational expressions, divide them
- Rewrite as the first rational expression multiplied by the reciprocal of the second.
- Factor the numerators and denominators.
- Multiply the numerators.
- Multiply the denominators.
- Simplify.
Example: Dividing Rational Expressions
Divide the rational expressions and express the quotient in simplest form:Answer: [latex-display]\begin{array}\text{ }\frac{2x^{2}+x-6}{x^{2}-1}\cdot\frac{x^{2}+2x+1}{x^{2}-4} \hfill& \text{Rewrite as the first fraction multiplied by the reciprocal of the second fraction.} \\ \frac{\left(2x-3\right)\cancel{\left(x+2\right)}}{\cancel{\left(x+1\right)}\left(x-1\right)}\cdot\frac{\cancel{\left(x+1\right)}\left(x+1\right)}{\cancel{\left(x+2\right)}\left(x-2\right)} \hfill& \text{Factor and cancel common factors.} \\ \frac{\left(2x+3\right)\left(x+1\right)}{\left(x-1\right)\left(x-2\right)} \hfill& \text{Multiply numerators and denominators.} \\ \frac{2x^{2}+5x+3}{x^{2}-3x+2} \hfill& \text{Simplify.}\end{array}[/latex-display]
Try It
Divide the rational expressions and express the quotient in simplest form:Answer: [latex]1[/latex]
Adding and Subtracting Rational Expressions
Adding and subtracting rational expressions works just like adding and subtracting numerical fractions. To add fractions, we need to find a common denominator. Let’s look at an example of fraction addition.How To: Given two rational expressions, add or subtract them
- Factor the numerator and denominator.
- Find the LCD of the expressions.
- Multiply the expressions by a form of 1 that changes the denominators to the LCD.
- Add or subtract the numerators.
- Simplify.
Example: Adding Rational Expressions
Add the rational expressions:Answer: First, we have to find the LCD. In this case, the LCD will be [latex]xy[/latex]. We then multiply each expression by the appropriate form of 1 to obtain [latex]xy[/latex] as the denominator for each fraction.
Analysis of the Solution
Multiplying by [latex]\frac{y}{y}[/latex] or [latex]\frac{x}{x}[/latex] does not change the value of the original expression because any number divided by itself is 1, and multiplying an expression by 1 gives the original expression.Example: Subtracting Rational Expressions
Subtract the rational expressions:Answer:
[latex]\begin{array}{cc}\frac{6}{{\left(x+2\right)}^{2}}-\frac{2}{\left(x+2\right)\left(x - 2\right)}\hfill & \text{Factor}.\hfill \\ \frac{6}{{\left(x+2\right)}^{2}}\cdot \frac{x - 2}{x - 2}-\frac{2}{\left(x+2\right)\left(x - 2\right)}\cdot \frac{x+2}{x+2}\hfill & \text{Multiply each fraction to get the LCD as the denominator}.\hfill \\ \frac{6\left(x - 2\right)}{{\left(x+2\right)}^{2}\left(x - 2\right)}-\frac{2\left(x+2\right)}{{\left(x+2\right)}^{2}\left(x - 2\right)}\hfill & \text{Multiply}.\hfill \\ \frac{6x - 12-\left(2x+4\right)}{{\left(x+2\right)}^{2}\left(x - 2\right)}\hfill & \text{Apply distributive property}.\hfill \\ \frac{4x - 16}{{\left(x+2\right)}^{2}\left(x - 2\right)}\hfill & \text{Subtract}.\hfill \\ \frac{4\left(x - 4\right)}{{\left(x+2\right)}^{2}\left(x - 2\right)}\hfill & \text{Simplify}.\hfill \end{array}[/latex]
Q & A
Do we have to use the LCD to add or subtract rational expressions? No. Any common denominator will work, but it is easiest to use the LCD.Try It
Subtract the rational expressions: [latex]\frac{3}{x+5}-\frac{1}{x - 3}[/latex].Answer: [latex]\frac{2\left(x - 7\right)}{\left(x+5\right)\left(x - 3\right)}[/latex]
Simplifying Complex Rational Expressions
A complex rational expression is a rational expression that contains additional rational expressions in the numerator, the denominator, or both. We can simplify complex rational expressions by rewriting the numerator and denominator as single rational expressions and dividing. The complex rational expression [latex]\frac{a}{\frac{1}{b}+c}[/latex] can be simplified by rewriting the numerator as the fraction [latex]\frac{a}{1}[/latex] and combining the expressions in the denominator as [latex]\frac{1+bc}{b}[/latex]. We can then rewrite the expression as a multiplication problem using the reciprocal of the denominator. We get [latex]\frac{a}{1}\cdot \frac{b}{1+bc}[/latex] which is equal to [latex]\frac{ab}{1+bc}[/latex].How To: Given a complex rational expression, simplify it
- Combine the expressions in the numerator into a single rational expression by adding or subtracting.
- Combine the expressions in the denominator into a single rational expression by adding or subtracting.
- Rewrite as the numerator divided by the denominator.
- Rewrite as multiplication.
- Multiply.
- Simplify.
Example: Simplifying Complex Rational Expressions
Simplify: [latex]\frac{y+\frac{1}{x}}{\frac{x}{y}}[/latex] .Answer: Begin by combining the expressions in the numerator into one expression.
Try It
Simplify: [latex]\frac{\frac{x}{y}-\frac{y}{x}}{y}[/latex]Answer: [latex]\frac{{x}^{2}-{y}^{2}}{x{y}^{2}}[/latex]
Q & A
Can a complex rational expression always be simplified? Yes. We can always rewrite a complex rational expression as a simplified rational expression.Key Concepts
- Rational expressions can be simplified by canceling common factors in the numerator and denominator.
- We can multiply rational expressions by multiplying the numerators and multiplying the denominators.
- To divide rational expressions, multiply by the reciprocal of the second expression.
- Adding or subtracting rational expressions requires finding a common denominator.
- Complex rational expressions have fractions in the numerator or the denominator. These expressions can be simplified.
Glossary
- least common denominator
- the smallest multiple that two denominators have in common
- rational expression
- the quotient of two polynomial expressions
Licenses & Attributions
CC licensed content, Original
- Revision and Adaptation. Provided by: Lumen Learning License: CC BY: Attribution.
CC licensed content, Shared previously
- College Algebra. Provided by: OpenStax Authored by: Abramson, Jay et al.. License: CC BY: Attribution. License terms: Download for free at http://cnx.org/contents/[email protected].
- Question ID 110917, 110916, 110918, 110919. Authored by: Lumen Learning. License: CC BY: Attribution. License terms: IMathAS Community License CC- BY + GPL.
- Question ID 93841, 93844, 93845, 93847. Authored by: Michael Jenck. License: CC BY: Attribution. License terms: IMathAS Community License, CC-BY + GPL.
- Question ID 39519. Authored by: Roy Shahbazian. License: CC BY: Attribution. License terms: IMathAS Community License CC-BY + GPL.
- Question ID 3078, 3080. Authored by: Tophe Anderson. License: CC BY: Attribution. License terms: IMathAS Community License CC-BY + GPL.
- Question ID 59554. Authored by: Gary Parker. License: CC BY: Attribution. License terms: IMathAS Community License CC- BY + GPL.
CC licensed content, Specific attribution
- College Algebra. Provided by: OpenStax Authored by: OpenStax College Algebra. Located at: https://cnx.org/contents/[email protected]:1/Preface. License: CC BY: Attribution.