What are the solutions to the equation y^2+4y+4=0 ?

The solutions to the equation y^2+4y+4=0 are y=-2

Find the zeros of y^2+4y+4=0

The zeros of y^2+4y+4=0 are y=-2

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y^{2} + 4 y + 4 = 0

y = - 2

Solution steps

y^{2} + 4 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

y_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

y = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

y = - 2

The solution to the quadratic equation is:

y = - 2

3 x^{2} - 7 x - 9 = 4 x^{2} - 4 x - 9

a^{2} - 1

- 3 (6 + 3 x) = - 72

k^{2} + 12 = 0

9 - ∣ 3 (b - 4) - b ∣ \leq 7

What are the solutions to the equation y^2+4y+4=0 ?
The solutions to the equation y^2+4y+4=0 are y=-2
Find the zeros of y^2+4y+4=0
The zeros of y^2+4y+4=0 are y=-2