What are the solutions to the equation 10(3x^2-13x)=-40 ?

The solutions to the equation 10(3x^2-13x)=-40 are x=4,x= 1/3

Find the zeros of 10(3x^2-13x)=-40

The zeros of 10(3x^2-13x)=-40 are x=4,x= 1/3

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10 (3 x^{2} - 13 x) = - 40

x = 4, x = \frac{1}{3}

Decimal Notation

x = 4, x = 0.33333 \dots

Solution steps

10 (3 x^{2} - 13 x) = - 40

Expand

10 (3 x^{2} - 13 x) : 30 x^{2} - 130 x

30 x^{2} - 130 x = - 40

Move

40

to the left side

30 x^{2} - 130 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 130 ) \pm ( - 130 ) ^{2} - 4 \cdot 30 \cdot 40}{2 \cdot 30}

(- 130)^{2} - 4 \cdot 30 \cdot 40 = 110

x_{1, 2} = \frac{- ( - 130 ) \pm 110}{2 \cdot 30}

Separate the solutions

x_{1} = \frac{- ( - 130 ) + 110}{2 \cdot 30}, x_{2} = \frac{- ( - 130 ) - 110}{2 \cdot 30}

x = \frac{- ( - 130 ) + 110}{2 \cdot 30} : 4

x = \frac{- ( - 130 ) - 110}{2 \cdot 30} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 4, x = \frac{1}{3}

- 42 v + 33 < 8 v + 91

18 x^{4} - 15 x^{3} + 36 x^{2} - 30 x

x^{2} + 17 x y + 72 y^{2}

3 (x - 2) + x = 2 (2 x - 8) + 22

x^{2} + x - 7 = 0

What are the solutions to the equation 10(3x^2-13x)=-40 ?
The solutions to the equation 10(3x^2-13x)=-40 are x=4,x= 1/3
Find the zeros of 10(3x^2-13x)=-40
The zeros of 10(3x^2-13x)=-40 are x=4,x= 1/3