What is (9^{2-1}+36^{2-1}+125^{3-1})/(4^{2-1)} ?

The solution to (9^{2-1}+36^{2-1}+125^{3-1})/(4^{2-1)} is 7835/2

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simplify (9^{2-1}+36^{2-1}+125^{3-1})/(4^{2-1)}

simplify

\frac{9 ^{2 - 1} + 3 6 ^{2 - 1} + 12 5 ^{3 - 1}}{4 ^{2 - 1}}

\frac{7835}{2}

Decimal Notation

3917.5

Solution steps

\frac{9 ^{2 - 1} + 3 6 ^{2 - 1} + 12 5 ^{3 - 1}}{4 ^{2 - 1}}

9^{2 - 1} + 3 6^{2 - 1} + 12 5^{3 - 1} = 15670

= \frac{15670}{4 ^{2 - 1}}

\frac{15670}{4 ^{2 - 1}} = \frac{15670}{4}

= \frac{15670}{4}

Factor the number:

15670 = 2 \cdot 7835

= \frac{2 \cdot 7835}{4}

Factor the number:

4 = 2 \cdot 2

= \frac{2 \cdot 7835}{2 \cdot 2}

Cancel the common factor:

2

= \frac{7835}{2}

5 x^{2} + 14 x = 3

4 ∣ n ∣ - 19 = 13

z^{2} + 36 = 13 z

- (6)^{- 1}

5 ((- 7) + 9) \leq 10

What is (9^{2-1}+36^{2-1}+125^{3-1})/(4^{2-1)} ?
The solution to (9^{2-1}+36^{2-1}+125^{3-1})/(4^{2-1)} is 7835/2