What are the solutions to the equation 7+2x^2=11 ?

The solutions to the equation 7+2x^2=11 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 7+2x^2=11

The zeros of 7+2x^2=11 are x=sqrt(2),x=-sqrt(2)

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7 + 2 x^{2} = 11

x = 2, x = - 2

Solution steps

7 + 2 x^{2} = 11

Move

7

to the right side

2 x^{2} = 4

Divide both sides by

2

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

18 x^{7} y^{6}

7 x + 6 = 76

\frac{11 π}{12} = \frac{3 π}{4} + \frac{π}{6}

64 (1050) - 0.02 (1050)^{2}

((9 x - 4) + 2)^{2} = 3

What are the solutions to the equation 7+2x^2=11 ?
The solutions to the equation 7+2x^2=11 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 7+2x^2=11
The zeros of 7+2x^2=11 are x=sqrt(2),x=-sqrt(2)