What are the solutions to the equation ((9x-4)+2)^2=3 ?

The solutions to the equation ((9x-4)+2)^2=3 are x=(sqrt(3)+2)/9 ,x=(-sqrt(3)+2)/9

Find the zeros of ((9x-4)+2)^2=3

The zeros of ((9x-4)+2)^2=3 are x=(sqrt(3)+2)/9 ,x=(-sqrt(3)+2)/9

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((9 x - 4) + 2)^{2} = 3

x = \frac{3 + 2}{9}, x = \frac{- 3 + 2}{9}

Decimal Notation

x = 0.41467 \dots, x = 0.02977 \dots

Solution steps

((9 x - 4) + 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

9 x - 4 + 2 = 3 : x = \frac{3 + 2}{9}

Solve

9 x - 4 + 2 = - 3 : x = \frac{- 3 + 2}{9}

The solutions to the quadratic equation are:

x = \frac{3 + 2}{9}, x = \frac{- 3 + 2}{9}

3 + \frac{1}{4}

24 x^{2} + 50 x + 33 \leq 0

\frac{11}{24} + w = \frac{11}{12}

x^{2} + 10 x = - 9

x^{2} + 12 = 12

What are the solutions to the equation ((9x-4)+2)^2=3 ?
The solutions to the equation ((9x-4)+2)^2=3 are x=(sqrt(3)+2)/9 ,x=(-sqrt(3)+2)/9
Find the zeros of ((9x-4)+2)^2=3
The zeros of ((9x-4)+2)^2=3 are x=(sqrt(3)+2)/9 ,x=(-sqrt(3)+2)/9