What are the solutions to the equation n^2+3n-18=0 ?

The solutions to the equation n^2+3n-18=0 are n=3,n=-6

Find the zeros of n^2+3n-18=0

The zeros of n^2+3n-18=0 are n=3,n=-6

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n^{2} + 3 n - 18 = 0

n = 3, n = - 6

Solution steps

n^{2} + 3 n - 18 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

n_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 3 + 9}{2 \cdot 1}, n_{2} = \frac{- 3 - 9}{2 \cdot 1}

n = \frac{- 3 + 9}{2 \cdot 1} : 3

n = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = 3, n = - 6

x^{2} - 22 x - 23 = 0

\frac{15 !}{4 ! ( 15 - 4 ) !}

X^{2} + 8 X - 128 = 0

x^{3} + x^{2} + 9 x + 9

\frac{17}{20} = t + (- \frac{13}{20})

What are the solutions to the equation n^2+3n-18=0 ?
The solutions to the equation n^2+3n-18=0 are n=3,n=-6
Find the zeros of n^2+3n-18=0
The zeros of n^2+3n-18=0 are n=3,n=-6