What are the solutions to the equation 4x^2+12x+9=4 ?

The solutions to the equation 4x^2+12x+9=4 are x=-1/2 ,x=-5/2

Find the zeros of 4x^2+12x+9=4

The zeros of 4x^2+12x+9=4 are x=-1/2 ,x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 12 x + 9 = 4

x = - \frac{1}{2}, x = - \frac{5}{2}

Decimal Notation

x = - 0.5, x = - 2.5

Solution steps

4 x^{2} + 12 x + 9 = 4

Move

4

to the left side

4 x^{2} + 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 5 = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 \cdot 4}, x_{2} = \frac{- 12 - 8}{2 \cdot 4}

x = \frac{- 12 + 8}{2 \cdot 4} : - \frac{1}{2}

x = \frac{- 12 - 8}{2 \cdot 4} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{5}{2}

9 x = 0

x^{2} + 15 x + 30 = 3 x - 2

10 \cdot \frac{π}{180}

\frac{4}{\frac{1}{4}}

\frac{5}{6} + \frac{7}{9} + \frac{4}{3}

What are the solutions to the equation 4x^2+12x+9=4 ?
The solutions to the equation 4x^2+12x+9=4 are x=-1/2 ,x=-5/2
Find the zeros of 4x^2+12x+9=4
The zeros of 4x^2+12x+9=4 are x=-1/2 ,x=-5/2