What is 5sqrt(x)+2>17 ?

The solution to 5sqrt(x)+2>17 is x>9

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5sqrt(x)+2>17

5 x + 2 > 17

x > 9

Interval Notation

(9, \infty)

Solution steps

5 x + 2 > 17

Move

2

to the right side

5 x > 15

Divide both sides by

5

x > 3

Square both sides

(x)^{2} > 3^{2}

Simplify

x > 9

Find singularity points

Find non-negative values for radicals:

x \geq 0

Combine the intervals

x > 9 and x \geq 0

Merge Overlapping Intervals

x > 9

49 = ∣ s + 40 ∣ - 1

- 3 x^{2} + 7 x - 2 = 0

\frac{2 x + 3}{5} > 3

(- 1)^{\frac{5}{3}}

(\frac{1}{25})^{- \frac{3}{2}}