What are the solutions to the equation -3x^2+7x-2=0 ?

The solutions to the equation -3x^2+7x-2=0 are x= 1/3 ,x=2

Find the zeros of -3x^2+7x-2=0

The zeros of -3x^2+7x-2=0 are x= 1/3 ,x=2

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- 3 x^{2} + 7 x - 2 = 0

x = \frac{1}{3}, x = 2

Solution steps

- 3 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

7^{2} - 4 (- 3) (- 2) = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 ( - 3 )}, x_{2} = \frac{- 7 - 5}{2 ( - 3 )}

x = \frac{- 7 + 5}{2 ( - 3 )} : \frac{1}{3}

x = \frac{- 7 - 5}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = 2

\frac{2 x + 3}{5} > 3

y^{2} - 13 y = - 36

\frac{1}{16} = x^{2}

2 \cdot 2^{\frac{2}{3}}

\frac{5}{3} - 3

What are the solutions to the equation -3x^2+7x-2=0 ?
The solutions to the equation -3x^2+7x-2=0 are x= 1/3 ,x=2
Find the zeros of -3x^2+7x-2=0
The zeros of -3x^2+7x-2=0 are x= 1/3 ,x=2