What are the solutions to the equation y^2-13y=-36 ?

The solutions to the equation y^2-13y=-36 are y=9,y=4

Find the zeros of y^2-13y=-36

The zeros of y^2-13y=-36 are y=9,y=4

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y^{2} - 13 y = - 36

y = 9, y = 4

Solution steps

y^{2} - 13 y = - 36

Move

36

to the left side

y^{2} - 13 y + 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 36 = 5

y_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 1}, y_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 1}

y = \frac{- ( - 13 ) + 5}{2 \cdot 1} : 9

y = \frac{- ( - 13 ) - 5}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

y = 9, y = 4

\frac{1}{16} = x^{2}

2 \cdot 2^{\frac{2}{3}}

\frac{5}{3} - 3

∣ 2 x + 1 ∣ = ∣ - 3 x + 1 ∣

5 (x + 3)^{2} - 5 y^{2}

What are the solutions to the equation y^2-13y=-36 ?
The solutions to the equation y^2-13y=-36 are y=9,y=4
Find the zeros of y^2-13y=-36
The zeros of y^2-13y=-36 are y=9,y=4