What is 4-sqrt(5y-10)<=-1 ?

The solution to 4-sqrt(5y-10) = 7

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4-sqrt(5y-10)<=-1

4 - 5 y - 10 \leq - 1

y \geq 7

Interval Notation

[7, \infty)

Solution steps

4 - 5 y - 10 \leq - 1

Move

4

to the right side

- 5 y - 10 \leq - 5

Multiply both sides by

- 1

5 y - 10 \geq 5

Square both sides

(5 y - 10)^{2} \geq 5^{2}

Simplify

5 y - 10 \geq 25

5 y - 10 \geq 25 : y \geq 7

y \geq 7

Find singularity points

Find non-negative values for radicals:

y \geq 2

Combine the intervals

y \geq 7 and y \geq 2

Merge Overlapping Intervals

y \geq 7

20 y^{2} + 3 y - 2

x^{2} \leq 3

- 55 + 445

m^{2} - 6 m = 49

\frac{1}{2} x + \frac{1}{4} \geq \frac{3}{2} x + \frac{3}{4}