What are the solutions to the equation 9=-x^2+5x+15 ?

The solutions to the equation 9=-x^2+5x+15 are x=-1,x=6

Find the zeros of 9=-x^2+5x+15

The zeros of 9=-x^2+5x+15 are x=-1,x=6

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9 = - x^{2} + 5 x + 15

x = - 1, x = 6

Solution steps

9 = - x^{2} + 5 x + 15

Switch sides

- x^{2} + 5 x + 15 = 9

Move

9

to the left side

- x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 6 = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 ( - 1 )}, x_{2} = \frac{- 5 - 7}{2 ( - 1 )}

x = \frac{- 5 + 7}{2 ( - 1 )} : - 1

x = \frac{- 5 - 7}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = - 1, x = 6

\frac{p}{6.7} = - 9.7

m^{2} - 20 m + 100

4 x + 5 = - 11

\frac{13 + 14 + 9}{3}

x^{2} - 23 x + 132 = 0

What are the solutions to the equation 9=-x^2+5x+15 ?
The solutions to the equation 9=-x^2+5x+15 are x=-1,x=6
Find the zeros of 9=-x^2+5x+15
The zeros of 9=-x^2+5x+15 are x=-1,x=6