What are the solutions to the equation x^2-23x+132=0 ?

The solutions to the equation x^2-23x+132=0 are x=12,x=11

Find the zeros of x^2-23x+132=0

The zeros of x^2-23x+132=0 are x=12,x=11

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x^{2} - 23 x + 132 = 0

x = 12, x = 11

Solution steps

x^{2} - 23 x + 132 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 1 \cdot 132}{2 \cdot 1}

(- 23)^{2} - 4 \cdot 1 \cdot 132 = 1

x_{1, 2} = \frac{- ( - 23 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 23 ) - 1}{2 \cdot 1}

x = \frac{- ( - 23 ) + 1}{2 \cdot 1} : 12

x = \frac{- ( - 23 ) - 1}{2 \cdot 1} : 11

The solutions to the quadratic equation are:

x = 12, x = 11

x^{2} - 5 x - 36 \geq 0

3 x^{2} + 4 x - 3 = 0

4 x^{2} + 48 x + 128 = 0

\frac{1}{2} - x < 5

4 x^{2} - 3 x^{2} = 0

What are the solutions to the equation x^2-23x+132=0 ?
The solutions to the equation x^2-23x+132=0 are x=12,x=11
Find the zeros of x^2-23x+132=0
The zeros of x^2-23x+132=0 are x=12,x=11