What are the solutions to the equation 2x^2+12x+15=0 ?

The solutions to the equation 2x^2+12x+15=0 are x=(-6+sqrt(6))/2 ,x=-(3sqrt(2)+sqrt(3))/(sqrt(2))

Find the zeros of 2x^2+12x+15=0

The zeros of 2x^2+12x+15=0 are x=(-6+sqrt(6))/2 ,x=-(3sqrt(2)+sqrt(3))/(sqrt(2))

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2 x^{2} + 12 x + 15 = 0

x = \frac{- 6 + 6}{2}, x = - \frac{3 2 + 3}{2}

Solution steps

2 x^{2} + 12 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 15 = 26

x_{1, 2} = \frac{- 12 \pm 2 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 2 6}{2 \cdot 2}, x_{2} = \frac{- 12 - 2 6}{2 \cdot 2}

x = \frac{- 12 + 2 6}{2 \cdot 2} : \frac{- 6 + 6}{2}

x = \frac{- 12 - 2 6}{2 \cdot 2} : - \frac{3 2 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 6 + 6}{2}, x = - \frac{3 2 + 3}{2}

64 x^{2} - 1 = 0

- 4 s \geq - 36

x + \frac{8}{7} > \frac{7}{6}

2 (6 d + 3) = 18 - 3 (16 - 3 d)

- x^{3} + 2 x^{2} + 15 x

What are the solutions to the equation 2x^2+12x+15=0 ?
The solutions to the equation 2x^2+12x+15=0 are x=(-6+sqrt(6))/2 ,x=-(3sqrt(2)+sqrt(3))/(sqrt(2))
Find the zeros of 2x^2+12x+15=0
The zeros of 2x^2+12x+15=0 are x=(-6+sqrt(6))/2 ,x=-(3sqrt(2)+sqrt(3))/(sqrt(2))