What is 1/3 (x+4)-5/6 (x-3)> 1/2 x+1 ?

The solution to 1/3 (x+4)-5/6 (x-3)> 1/2 x+1 is x< 17/6

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1/3 (x+4)-5/6 (x-3)> 1/2 x+1

\frac{1}{3} (x + 4) - \frac{5}{6} (x - 3) > \frac{1}{2} x + 1

x < \frac{17}{6}

Interval Notation

(- \infty, \frac{17}{6})

Decimal Notation

x < 2.83333 \dots

Solution steps

\frac{1}{3} (x + 4) - \frac{5}{6} (x - 3) > \frac{1}{2} x + 1

Expand

\frac{1}{3} (x + 4) - \frac{5}{6} (x - 3) : - \frac{x}{2} + \frac{23}{6}

- \frac{x}{2} + \frac{23}{6} > \frac{1}{2} x + 1

Move

\frac{23}{6}

to the right side

- \frac{x}{2} > - \frac{17}{6} + \frac{1}{2} x

Move

\frac{1}{2} x

to the left side

- x > - \frac{17}{6}

Multiply both sides by

- 1

x < \frac{17}{6}

x^{2} - 12 \leq 4 x

\frac{m ^{2} - 7 m - 18}{m ^{2} - 10 m + 9} + \frac{6}{m - 1}

\frac{( x + 6 ) ^{2}}{25} + \frac{( y - 5 ) ^{2}}{36}

\frac{2 9 ^{3} \cdot e ^{- 29}}{3 !}

(- 9 x y^{3} - 9 x^{4} y^{3}) + (3 x y^{3} + 7 y^{4} - 8 x^{4} y^{4}) + (3 x^{4} y^{3} + 2 x y^{3})

What is 1/3 (x+4)-5/6 (x-3)> 1/2 x+1 ?
The solution to 1/3 (x+4)-5/6 (x-3)> 1/2 x+1 is x< 17/6