What is (m^2-7m-18)/(m^2-10m+9)+6/(m-1) ?

The solution to (m^2-7m-18)/(m^2-10m+9)+6/(m-1) is (m+8)/(m-1)

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simplify (m^2-7m-18)/(m^2-10m+9)+6/(m-1)

simplify

\frac{m ^{2} - 7 m - 18}{m ^{2} - 10 m + 9} + \frac{6}{m - 1}

\frac{m + 8}{m - 1}

Solution steps

\frac{m ^{2} - 7 m - 18}{m ^{2} - 10 m + 9} + \frac{6}{m - 1}

Cancel

\frac{m ^{2} - 7 m - 18}{m ^{2} - 10 m + 9} : \frac{m + 2}{m - 1}

= \frac{m + 2}{m - 1} + \frac{6}{m - 1}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{m + 2 + 6}{m - 1}

Add the numbers:

2 + 6 = 8

= \frac{m + 8}{m - 1}

\frac{( x + 6 ) ^{2}}{25} + \frac{( y - 5 ) ^{2}}{36}

\frac{2 9 ^{3} \cdot e ^{- 29}}{3 !}

(- 9 x y^{3} - 9 x^{4} y^{3}) + (3 x y^{3} + 7 y^{4} - 8 x^{4} y^{4}) + (3 x^{4} y^{3} + 2 x y^{3})

\frac{x - 3}{4} < 2

2 x^{2} + 3 x = 0

What is (m^2-7m-18)/(m^2-10m+9)+6/(m-1) ?
The solution to (m^2-7m-18)/(m^2-10m+9)+6/(m-1) is (m+8)/(m-1)