What are the solutions to the equation s^2+7s=-17 ?

The solutions to the equation s^2+7s=-17 are s=-7/2+i(sqrt(19))/2 ,s=-7/2-i(sqrt(19))/2

Find the zeros of s^2+7s=-17

The zeros of s^2+7s=-17 are s=-7/2+i(sqrt(19))/2 ,s=-7/2-i(sqrt(19))/2

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s^{2} + 7 s = - 17

s = - \frac{7}{2} + i \frac{19}{2}, s = - \frac{7}{2} - i \frac{19}{2}

Solution steps

s^{2} + 7 s = - 17

Move

17

to the left side

s^{2} + 7 s + 17 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

Simplify

7^{2} - 4 \cdot 1 \cdot 17 : 19 i

s_{1, 2} = \frac{- 7 \pm 19 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 7 + 19 i}{2 \cdot 1}, s_{2} = \frac{- 7 - 19 i}{2 \cdot 1}

s = \frac{- 7 + 19 i}{2 \cdot 1} : - \frac{7}{2} + i \frac{19}{2}

s = \frac{- 7 - 19 i}{2 \cdot 1} : - \frac{7}{2} - i \frac{19}{2}

The solutions to the quadratic equation are:

s = - \frac{7}{2} + i \frac{19}{2}, s = - \frac{7}{2} - i \frac{19}{2}

- 2 = 3 x^{2} - x - 2

0 \leq 2 x - 6 \leq 4

y^{2} - 25 x^{2}

2 x - x 5 = 9

4 x^{2} - 18 x + 8 = 0

What are the solutions to the equation s^2+7s=-17 ?
The solutions to the equation s^2+7s=-17 are s=-7/2+i(sqrt(19))/2 ,s=-7/2-i(sqrt(19))/2
Find the zeros of s^2+7s=-17
The zeros of s^2+7s=-17 are s=-7/2+i(sqrt(19))/2 ,s=-7/2-i(sqrt(19))/2