What are the solutions to the equation x^2-14x+74=0 ?

The solutions to the equation x^2-14x+74=0 are x=7+5i,x=7-5i

Find the zeros of x^2-14x+74=0

The zeros of x^2-14x+74=0 are x=7+5i,x=7-5i

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x^{2} - 14 x + 74 = 0

x = 7 + 5 i, x = 7 - 5 i

Solution steps

x^{2} - 14 x + 74 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 74}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 74 : 10 i

x_{1, 2} = \frac{- ( - 14 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 10 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 10 i}{2 \cdot 1} : 7 + 5 i

x = \frac{- ( - 14 ) - 10 i}{2 \cdot 1} : 7 - 5 i

The solutions to the quadratic equation are:

x = 7 + 5 i, x = 7 - 5 i

∣ 2 - 3 x ∣ + 1 \geq 4

5 x - 22 \geq - 4 (2 - 3 x)

2 k^{2} + 4 k

4 x - 0.8 = 4

\frac{x + 3}{3 - x} \geq \frac{x}{x + 1}

What are the solutions to the equation x^2-14x+74=0 ?
The solutions to the equation x^2-14x+74=0 are x=7+5i,x=7-5i
Find the zeros of x^2-14x+74=0
The zeros of x^2-14x+74=0 are x=7+5i,x=7-5i