What are the solutions to the equation 9x^2+48x+68=0 ?

The solutions to the equation 9x^2+48x+68=0 are x=-8/3+i 2/3 ,x=-8/3-i 2/3

Find the zeros of 9x^2+48x+68=0

The zeros of 9x^2+48x+68=0 are x=-8/3+i 2/3 ,x=-8/3-i 2/3

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9 x^{2} + 48 x + 68 = 0

x = - \frac{8}{3} + i \frac{2}{3}, x = - \frac{8}{3} - i \frac{2}{3}

Solution steps

9 x^{2} + 48 x + 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 9 \cdot 68}{2 \cdot 9}

Simplify

4 8^{2} - 4 \cdot 9 \cdot 68 : 12 i

x_{1, 2} = \frac{- 48 \pm 12 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 48 + 12 i}{2 \cdot 9}, x_{2} = \frac{- 48 - 12 i}{2 \cdot 9}

x = \frac{- 48 + 12 i}{2 \cdot 9} : - \frac{8}{3} + i \frac{2}{3}

x = \frac{- 48 - 12 i}{2 \cdot 9} : - \frac{8}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{8}{3} + i \frac{2}{3}, x = - \frac{8}{3} - i \frac{2}{3}

4 x^{3} + 6 x^{2} - 40 x

4 x^{2} + 12 x + 9 = 169

8^{\frac{1}{2}}

\frac{x - 4}{8} - \frac{5 - 2 x}{3} = 1

8 + 32 + 32

What are the solutions to the equation 9x^2+48x+68=0 ?
The solutions to the equation 9x^2+48x+68=0 are x=-8/3+i 2/3 ,x=-8/3-i 2/3
Find the zeros of 9x^2+48x+68=0
The zeros of 9x^2+48x+68=0 are x=-8/3+i 2/3 ,x=-8/3-i 2/3