What are the solutions to the equation 4x^2+12x+9=169 ?

The solutions to the equation 4x^2+12x+9=169 are x=5,x=-8

Find the zeros of 4x^2+12x+9=169

The zeros of 4x^2+12x+9=169 are x=5,x=-8

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4 x^{2} + 12 x + 9 = 169

x = 5, x = - 8

Solution steps

4 x^{2} + 12 x + 9 = 169

Move

169

to the left side

4 x^{2} + 12 x - 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 160 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 160) = 52

x_{1, 2} = \frac{- 12 \pm 52}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 52}{2 \cdot 4}, x_{2} = \frac{- 12 - 52}{2 \cdot 4}

x = \frac{- 12 + 52}{2 \cdot 4} : 5

x = \frac{- 12 - 52}{2 \cdot 4} : - 8

The solutions to the quadratic equation are:

x = 5, x = - 8

8^{\frac{1}{2}}

\frac{x - 4}{8} - \frac{5 - 2 x}{3} = 1

8 + 32 + 32

\frac{15 a b ^{5} c ^{8}}{18 a b ^{3} c ^{9}}

- 2 x^{2} + 8 x - 2 = 0

What are the solutions to the equation 4x^2+12x+9=169 ?
The solutions to the equation 4x^2+12x+9=169 are x=5,x=-8
Find the zeros of 4x^2+12x+9=169
The zeros of 4x^2+12x+9=169 are x=5,x=-8