What are the solutions to the equation -2x^2+8x-2=0 ?

The solutions to the equation -2x^2+8x-2=0 are x=2-sqrt(3),x=2+sqrt(3)

Find the zeros of -2x^2+8x-2=0

The zeros of -2x^2+8x-2=0 are x=2-sqrt(3),x=2+sqrt(3)

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- 2 x^{2} + 8 x - 2 = 0

x = 2 - 3, x = 2 + 3

Decimal Notation

x = 0.26794 \dots, x = 3.73205 \dots

Solution steps

- 2 x^{2} + 8 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 2) = 43

x_{1, 2} = \frac{- 8 \pm 4 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 3}{2 ( - 2 )}, x_{2} = \frac{- 8 - 4 3}{2 ( - 2 )}

x = \frac{- 8 + 4 3}{2 ( - 2 )} : 2 - 3

x = \frac{- 8 - 4 3}{2 ( - 2 )} : 2 + 3

The solutions to the quadratic equation are:

x = 2 - 3, x = 2 + 3

- 7 y < 21

∣ 2 x + 1 ∣ \geq x + 5

1 < \frac{s}{2} - 1

x^{4} - 11 x^{2} + 28

x^{2} - 8 x + 8 = - 10

What are the solutions to the equation -2x^2+8x-2=0 ?
The solutions to the equation -2x^2+8x-2=0 are x=2-sqrt(3),x=2+sqrt(3)
Find the zeros of -2x^2+8x-2=0
The zeros of -2x^2+8x-2=0 are x=2-sqrt(3),x=2+sqrt(3)