What are the solutions to the equation 3x^2-15x+12=0 ?

The solutions to the equation 3x^2-15x+12=0 are x=4,x=1

Find the zeros of 3x^2-15x+12=0

The zeros of 3x^2-15x+12=0 are x=4,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 15 x + 12 = 0

x = 4, x = 1

Solution steps

3 x^{2} - 15 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

(- 15)^{2} - 4 \cdot 3 \cdot 12 = 9

x_{1, 2} = \frac{- ( - 15 ) \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 9}{2 \cdot 3}, x_{2} = \frac{- ( - 15 ) - 9}{2 \cdot 3}

x = \frac{- ( - 15 ) + 9}{2 \cdot 3} : 4

x = \frac{- ( - 15 ) - 9}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

(5 x - 3) \cdot (4 x + 7) = 0

8 x \frac{2}{3} - 43 x \frac{1}{3} + 15 = 0

2 g > - 8

\frac{1}{a - b} - \frac{1}{b - a}

15 q^{3} + 40 q^{2} + 3 q + 8

What are the solutions to the equation 3x^2-15x+12=0 ?
The solutions to the equation 3x^2-15x+12=0 are x=4,x=1
Find the zeros of 3x^2-15x+12=0
The zeros of 3x^2-15x+12=0 are x=4,x=1