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Popular >

t^2+t+1=(t+1)^2

Solution

t^{2} + t + 1 = (t + 1)^{2}

Solution

t = 0

Solution steps

t^{2} + t + 1 = (t + 1)^{2}

Expand

(t + 1)^{2} : t^{2} + 2 t + 1

t^{2} + t + 1 = t^{2} + 2 t + 1

Move

1

to the right side

t^{2} + t = t^{2} + 2 t

Subtract

t^{2} + 2 t

from both sides

t^{2} + t - (t^{2} + 2 t) = t^{2} + 2 t - (t^{2} + 2 t)

Simplify

- t = 0

Divide both sides by

- 1

t = 0

Popular Examples

factor 25t^2-120t+144 factor

25 t^{2} - 120 t + 144

simplify log_{1/4}(1024)simplify

lo g_{\frac{1}{4}} (1024)

8(2x-1)-1/4 x= 7/4 (3-2x)

8 (2 x - 1) - \frac{1}{4} x = \frac{7}{4} (3 - 2 x)

simplify 7/8-1 simplify

\frac{7}{8} - 1

5 x^{2} - 7 x + 5 = 0

Frequently Asked Questions (FAQ)

What is the answer to t^2+t+1=(t+1)^2 ?
The answer to t^2+t+1=(t+1)^2 is t=0
Solve for t: t^2+t+1=(t+1)^2
The solution is t=0