What are the solutions to the equation 5x^2-7x+5=0 ?

The solutions to the equation 5x^2-7x+5=0 are x= 7/10+i(sqrt(51))/(10),x= 7/10-i(sqrt(51))/(10)

Find the zeros of 5x^2-7x+5=0

The zeros of 5x^2-7x+5=0 are x= 7/10+i(sqrt(51))/(10),x= 7/10-i(sqrt(51))/(10)

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5 x^{2} - 7 x + 5 = 0

x = \frac{7}{10} + i \frac{51}{10}, x = \frac{7}{10} - i \frac{51}{10}

Solution steps

5 x^{2} - 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

(- 7)^{2} - 4 \cdot 5 \cdot 5 : 51 i

x_{1, 2} = \frac{- ( - 7 ) \pm 51 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 51 i}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 51 i}{2 \cdot 5}

x = \frac{- ( - 7 ) + 51 i}{2 \cdot 5} : \frac{7}{10} + i \frac{51}{10}

x = \frac{- ( - 7 ) - 51 i}{2 \cdot 5} : \frac{7}{10} - i \frac{51}{10}

The solutions to the quadratic equation are:

x = \frac{7}{10} + i \frac{51}{10}, x = \frac{7}{10} - i \frac{51}{10}

4 x (x + 1) = 3

3 \frac{x}{9} + 7 = 8

x^{2} + 6 x = - 5

(\frac{6}{- 4})^{2}

\frac{2 π}{\frac{1}{7}}

What are the solutions to the equation 5x^2-7x+5=0 ?
The solutions to the equation 5x^2-7x+5=0 are x= 7/10+i(sqrt(51))/(10),x= 7/10-i(sqrt(51))/(10)
Find the zeros of 5x^2-7x+5=0
The zeros of 5x^2-7x+5=0 are x= 7/10+i(sqrt(51))/(10),x= 7/10-i(sqrt(51))/(10)