What is |x^3+3x^2-9x-27|<= 7x+21 ?

The solution to |x^3+3x^2-9x-27|<= 7x+21 is -3<= x<=-sqrt(2)\lor sqrt(2)<= x<= 4

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|x^3+3x^2-9x-27|<= 7x+21

x^{3} + 3 x^{2} - 9 x - 27 \leq 7 x + 21

- 3 \leq x \leq - 2 or 2 \leq x \leq 4

Interval Notation

[- 3, - 2] \cup [2, 4]

Decimal Notation

- 3 \leq x \leq - 1.41421 \dots or 1.41421 \dots \leq x \leq 4

Solution steps

x^{3} + 3 x^{2} - 9 x - 27 \leq 7 x + 21

Find positive and negative intervals

x < - 3, - 3 \leq x < 3, x \geq 3

Solve the inequality for each interval

No Solution or (- 3 \leq x \leq - 2 or 2 \leq x < 3) or 3 \leq x \leq 4

Merge Overlapping Intervals

- 3 \leq x \leq - 2 or 2 \leq x \leq 4

\frac{2}{3} (1 - 2 p) + 3 p = - (4 - p)

2^{3} x^{- 2} y^{- 3}

(10 n)^{\frac{3}{2}}

v^{3} - 8

(3 x - 7)^{4} (x - 1)^{3} (x + 1) \leq 0

What is |x^3+3x^2-9x-27|<= 7x+21 ?
The solution to |x^3+3x^2-9x-27|<= 7x+21 is -3<= x<=-sqrt(2)\lor sqrt(2)<= x<= 4