What is 2^3x^{-2}y^{-3} ?

The solution to 2^3x^{-2}y^{-3} is 8/(x^2y^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2^3x^{-2}y^{-3}

simplify

2^{3} x^{- 2} y^{- 3}

\frac{8}{x ^{2} y ^{3}}

Solution steps

2^{3} x^{- 2} y^{- 3}

2^{3} = 8

= 8 x^{- 2} y^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 2} = \frac{1}{x ^{2}}

= 8 \cdot \frac{1}{x ^{2}} y^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 3} = \frac{1}{y ^{3}}

= 8 \cdot \frac{1}{x ^{2}} \cdot \frac{1}{y ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{8 \cdot 1 \cdot 1}{x ^{2} y ^{3}}

Multiply the numbers:

8 \cdot 1 \cdot 1 = 8

= \frac{8}{x ^{2} y ^{3}}

(10 n)^{\frac{3}{2}}

v^{3} - 8

(3 x - 7)^{4} (x - 1)^{3} (x + 1) \leq 0

x^{3} - 9 x > 0

v^{2} + 10 v + 17 = - 7