What are the solutions to the equation v^2+10v+17=-7 ?

The solutions to the equation v^2+10v+17=-7 are v=-4,v=-6

Find the zeros of v^2+10v+17=-7

The zeros of v^2+10v+17=-7 are v=-4,v=-6

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v^{2} + 10 v + 17 = - 7

v = - 4, v = - 6

Solution steps

v^{2} + 10 v + 17 = - 7

Move

7

to the left side

v^{2} + 10 v + 24 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

v_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 10 + 2}{2 \cdot 1}, v_{2} = \frac{- 10 - 2}{2 \cdot 1}

v = \frac{- 10 + 2}{2 \cdot 1} : - 4

v = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

v = - 4, v = - 6

(\frac{1}{125})^{\frac{2}{3}}

9 z^{2} - 30 z + 26 = 1

∣ w + 2 ∣ - ∣ w - 2 ∣ = 2 w

5.3 x^{2} - 17 x + 10 = 0

∣ 7 x + 2 ∣ > 2

What are the solutions to the equation v^2+10v+17=-7 ?
The solutions to the equation v^2+10v+17=-7 are v=-4,v=-6
Find the zeros of v^2+10v+17=-7
The zeros of v^2+10v+17=-7 are v=-4,v=-6