What are the solutions to the equation 5.3x^2-17x+10=0 ?

The solutions to the equation 5.3x^2-17x+10=0 are x=(5(17+sqrt(77)))/(53),x=(5(17-sqrt(77)))/(53)

Find the zeros of 5.3x^2-17x+10=0

The zeros of 5.3x^2-17x+10=0 are x=(5(17+sqrt(77)))/(53),x=(5(17-sqrt(77)))/(53)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5.3 x^{2} - 17 x + 10 = 0

x = \frac{5 ( 17 + 77 )}{53}, x = \frac{5 ( 17 - 77 )}{53}

Decimal Notation

x = 2.43160 \dots, x = 0.77594 \dots

Solution steps

5.3 x^{2} - 17 x + 10 = 0

Multiply both sides by

10

53 x^{2} - 170 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 170 ) \pm ( - 170 ) ^{2} - 4 \cdot 53 \cdot 100}{2 \cdot 53}

(- 170)^{2} - 4 \cdot 53 \cdot 100 = 1077

x_{1, 2} = \frac{- ( - 170 ) \pm 10 77}{2 \cdot 53}

Separate the solutions

x_{1} = \frac{- ( - 170 ) + 10 77}{2 \cdot 53}, x_{2} = \frac{- ( - 170 ) - 10 77}{2 \cdot 53}

x = \frac{- ( - 170 ) + 10 77}{2 \cdot 53} : \frac{5 ( 17 + 77 )}{53}

x = \frac{- ( - 170 ) - 10 77}{2 \cdot 53} : \frac{5 ( 17 - 77 )}{53}

The solutions to the quadratic equation are:

x = \frac{5 ( 17 + 77 )}{53}, x = \frac{5 ( 17 - 77 )}{53}

∣ 7 x + 2 ∣ > 2

(\frac{2 x ^{3}}{y ^{2}})^{4}

3 (r + 1) = 6

4 u^{2} + 12 u = - 9

x - 4 \geq 6 x - 3 (x + 1)

What are the solutions to the equation 5.3x^2-17x+10=0 ?
The solutions to the equation 5.3x^2-17x+10=0 are x=(5(17+sqrt(77)))/(53),x=(5(17-sqrt(77)))/(53)
Find the zeros of 5.3x^2-17x+10=0
The zeros of 5.3x^2-17x+10=0 are x=(5(17+sqrt(77)))/(53),x=(5(17-sqrt(77)))/(53)