What is (i^4+i^9+i^{16})/(2-i^5+i^{10)-i^{15}} ?

The solution to (i^4+i^9+i^{16})/(2-i^5+i^{10)-i^{15}} is 2+i

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simplify (i^4+i^9+i^{16})/(2-i^5+i^{10)-i^{15}}

simplify

\frac{i ^{4} + i ^{9} + i ^{16}}{2 - i ^{5} + i ^{10} - i ^{15}}

2 + i

Solution steps

\frac{i ^{4} + i ^{9} + i ^{16}}{2 - i ^{5} + i ^{10} - i ^{15}}

Simplify

i^{4} + i^{9} + i^{16} : i + 2

= \frac{i + 2}{2 - i ^{5} + i ^{10} - i ^{15}}

Simplify

2 - i^{5} + i^{10} - i^{15} : 1

= \frac{i + 2}{1}

Rewrite in standard complex form:

2 + i

= 2 + i

3 x^{3} + 6 x^{2} + 3 x

3 x - 2 < 10

9 y^{2} - 36 y + 36 = 0

\frac{( x ^{2} y ^{3} ) ( x y ^{4} ) ^{- 3}}{x ^{2} y}

\frac{x - 2}{x - 4} \geq 0

What is (i^4+i^9+i^{16})/(2-i^5+i^{10)-i^{15}} ?
The solution to (i^4+i^9+i^{16})/(2-i^5+i^{10)-i^{15}} is 2+i