What are the solutions to the equation 9y^2-36y+36=0 ?

The solutions to the equation 9y^2-36y+36=0 are y=2

Find the zeros of 9y^2-36y+36=0

The zeros of 9y^2-36y+36=0 are y=2

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9 y^{2} - 36 y + 36 = 0

y = 2

Solution steps

9 y^{2} - 36 y + 36 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 9 \cdot 36}{2 \cdot 9}

(- 36)^{2} - 4 \cdot 9 \cdot 36 = 0

y_{1, 2} = \frac{- ( - 36 ) \pm 0}{2 \cdot 9}

y = \frac{- ( - 36 )}{2 \cdot 9}

\frac{- ( - 36 )}{2 \cdot 9} = 2

y = 2

The solution to the quadratic equation is:

y = 2

\frac{( x ^{2} y ^{3} ) ( x y ^{4} ) ^{- 3}}{x ^{2} y}

\frac{x - 2}{x - 4} \geq 0

2 x^{2} + 8 x + 8 = 0

3 x^{2} - x + 5 = 0

(\frac{1}{8})^{- 4}

What are the solutions to the equation 9y^2-36y+36=0 ?
The solutions to the equation 9y^2-36y+36=0 are y=2
Find the zeros of 9y^2-36y+36=0
The zeros of 9y^2-36y+36=0 are y=2