What are the solutions to the equation 2x^2+8x+8=0 ?

The solutions to the equation 2x^2+8x+8=0 are x=-2

Find the zeros of 2x^2+8x+8=0

The zeros of 2x^2+8x+8=0 are x=-2

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2 x^{2} + 8 x + 8 = 0

x = - 2

Solution steps

2 x^{2} + 8 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 8 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 2}

x = \frac{- 8}{2 \cdot 2}

\frac{- 8}{2 \cdot 2} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

3 x^{2} - x + 5 = 0

(\frac{1}{8})^{- 4}

(\frac{3}{5})^{0}

- 3 x - 43 = - 100

- x + \frac{1}{5} + 5 x = \frac{41}{5}

What are the solutions to the equation 2x^2+8x+8=0 ?
The solutions to the equation 2x^2+8x+8=0 are x=-2
Find the zeros of 2x^2+8x+8=0
The zeros of 2x^2+8x+8=0 are x=-2