What are the solutions to the equation 4x^2+16x+12=0 ?

The solutions to the equation 4x^2+16x+12=0 are x=-1,x=-3

Find the zeros of 4x^2+16x+12=0

The zeros of 4x^2+16x+12=0 are x=-1,x=-3

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4 x^{2} + 16 x + 12 = 0

x = - 1, x = - 3

Solution steps

4 x^{2} + 16 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 12}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 \cdot 12 = 8

x_{1, 2} = \frac{- 16 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 8}{2 \cdot 4}, x_{2} = \frac{- 16 - 8}{2 \cdot 4}

x = \frac{- 16 + 8}{2 \cdot 4} : - 1

x = \frac{- 16 - 8}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

- 2 x > 2

9 - 4 x \geq 5 or 4 (- 1 + x) - 6 \geq 2

\frac{5 ! 6 !}{3 ! 8 !}

x^{2} + 12 x + 11

\frac{1 2 ^{5}}{1 2 ^{3}}

What are the solutions to the equation 4x^2+16x+12=0 ?
The solutions to the equation 4x^2+16x+12=0 are x=-1,x=-3
Find the zeros of 4x^2+16x+12=0
The zeros of 4x^2+16x+12=0 are x=-1,x=-3