What are the solutions to the equation 2x^2-8x+3=0 ?

The solutions to the equation 2x^2-8x+3=0 are x=(4+sqrt(10))/2 ,x=(4-sqrt(10))/2

Find the zeros of 2x^2-8x+3=0

The zeros of 2x^2-8x+3=0 are x=(4+sqrt(10))/2 ,x=(4-sqrt(10))/2

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2 x^{2} - 8 x + 3 = 0

x = \frac{4 + 10}{2}, x = \frac{4 - 10}{2}

Solution steps

2 x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 3 = 210

x_{1, 2} = \frac{- ( - 8 ) \pm 2 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 10}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 2 10}{2 \cdot 2}

x = \frac{- ( - 8 ) + 2 10}{2 \cdot 2} : \frac{4 + 10}{2}

x = \frac{- ( - 8 ) - 2 10}{2 \cdot 2} : \frac{4 - 10}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 10}{2}, x = \frac{4 - 10}{2}

(\frac{1}{81})^{- \frac{3}{4}}

d^{2} + 9 = 0

7 x^{2} - 28 x = 0

\frac{k}{2} > 4

3 h + 7 \geq - h - 10

What are the solutions to the equation 2x^2-8x+3=0 ?
The solutions to the equation 2x^2-8x+3=0 are x=(4+sqrt(10))/2 ,x=(4-sqrt(10))/2
Find the zeros of 2x^2-8x+3=0
The zeros of 2x^2-8x+3=0 are x=(4+sqrt(10))/2 ,x=(4-sqrt(10))/2