What is the answer to (3m+2)^2+(2m-1)^2=13m(m+6) ?

The answer to (3m+2)^2+(2m-1)^2=13m(m+6) is m= 1/14

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(3m+2)^2+(2m-1)^2=13m(m+6)

(3 m + 2)^{2} + (2 m - 1)^{2} = 13 m (m + 6)

m = \frac{1}{14}

Decimal Notation

m = 0.07142 \dots

Solution steps

(3 m + 2)^{2} + (2 m - 1)^{2} = 13 m (m + 6)

Expand

(3 m + 2)^{2} + (2 m - 1)^{2} : 13 m^{2} + 8 m + 5

Expand

13 m (m + 6) : 13 m^{2} + 78 m

13 m^{2} + 8 m + 5 = 13 m^{2} + 78 m

Move

5

to the right side

13 m^{2} + 8 m = 13 m^{2} + 78 m - 5

Subtract

13 m^{2} + 78 m

from both sides

13 m^{2} + 8 m - (13 m^{2} + 78 m) = 13 m^{2} + 78 m - 5 - (13 m^{2} + 78 m)

Simplify

- 70 m = - 5

Divide both sides by

- 70

m = \frac{1}{14}

- 3 x^{2} + 108 = 0

(\frac{1}{2})^{3} \cdot (\frac{3}{2})^{- 2}

- 8 > \frac{12}{7} u

7^{3} \cdot 7^{5}

∣ 4 x + 2 ∣ - 3 \geq 11

What is the answer to (3m+2)^2+(2m-1)^2=13m(m+6) ?
The answer to (3m+2)^2+(2m-1)^2=13m(m+6) is m= 1/14
Solve for m: (3m+2)^2+(2m-1)^2=13m(m+6)
The solution is m= 1/14