What are the solutions to the equation a^2+a+4=0 ?

The solutions to the equation a^2+a+4=0 are a=-1/2+i(sqrt(15))/2 ,a=-1/2-i(sqrt(15))/2

Find the zeros of a^2+a+4=0

The zeros of a^2+a+4=0 are a=-1/2+i(sqrt(15))/2 ,a=-1/2-i(sqrt(15))/2

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a^{2} + a + 4 = 0

a = - \frac{1}{2} + i \frac{15}{2}, a = - \frac{1}{2} - i \frac{15}{2}

Solution steps

a^{2} + a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 4 : 15 i

a_{1, 2} = \frac{- 1 \pm 15 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 1 + 15 i}{2 \cdot 1}, a_{2} = \frac{- 1 - 15 i}{2 \cdot 1}

a = \frac{- 1 + 15 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{15}{2}

a = \frac{- 1 - 15 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

a = - \frac{1}{2} + i \frac{15}{2}, a = - \frac{1}{2} - i \frac{15}{2}

2 \leq \frac{5 x + 3}{3} \leq 4

\frac{k}{4} + 3 = 14

x^{2} + 5 x^{2} + 4 x

8 b^{2} - 7 = 193

∣ x - 2 ∣ = \frac{1}{4}

What are the solutions to the equation a^2+a+4=0 ?
The solutions to the equation a^2+a+4=0 are a=-1/2+i(sqrt(15))/2 ,a=-1/2-i(sqrt(15))/2
Find the zeros of a^2+a+4=0
The zeros of a^2+a+4=0 are a=-1/2+i(sqrt(15))/2 ,a=-1/2-i(sqrt(15))/2