What are the solutions to the equation 4v^2+4v-3=0 ?

The solutions to the equation 4v^2+4v-3=0 are v= 1/2 ,v=-3/2

Find the zeros of 4v^2+4v-3=0

The zeros of 4v^2+4v-3=0 are v= 1/2 ,v=-3/2

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4 v^{2} + 4 v - 3 = 0

v = \frac{1}{2}, v = - \frac{3}{2}

Decimal Notation

v = 0.5, v = - 1.5

Solution steps

4 v^{2} + 4 v - 3 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 3) = 8

v_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- 4 + 8}{2 \cdot 4}, v_{2} = \frac{- 4 - 8}{2 \cdot 4}

v = \frac{- 4 + 8}{2 \cdot 4} : \frac{1}{2}

v = \frac{- 4 - 8}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

v = \frac{1}{2}, v = - \frac{3}{2}

\frac{b ^{2} + 3 b - 28}{b ^{2} - 49}

x^{2} - 8 x + 8 = 0

\frac{1}{5} n + 8 \leq 95

9 x^{2} + 9 x y + 9 y^{2}

25 + 45 + 180 - 80

What are the solutions to the equation 4v^2+4v-3=0 ?
The solutions to the equation 4v^2+4v-3=0 are v= 1/2 ,v=-3/2
Find the zeros of 4v^2+4v-3=0
The zeros of 4v^2+4v-3=0 are v= 1/2 ,v=-3/2