What are the solutions to the equation 0.05v^2+0.5v=48 ?

The solutions to the equation 0.05v^2+0.5v=48 are v=-5+sqrt(985),v=-5-sqrt(985)

Find the zeros of 0.05v^2+0.5v=48

The zeros of 0.05v^2+0.5v=48 are v=-5+sqrt(985),v=-5-sqrt(985)

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0.05 v^{2} + 0.5 v = 48

v = - 5 + 985, v = - 5 - 985

Decimal Notation

v = 26.38470 \dots, v = - 36.38470 \dots

Solution steps

0.05 v^{2} + 0.5 v = 48

Multiply both sides by

100

5 v^{2} + 50 v = 4800

Move

4800

to the left side

5 v^{2} + 50 v - 4800 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 5 ( - 4800 )}{2 \cdot 5}

5 0^{2} - 4 \cdot 5 (- 4800) = 10985

v_{1, 2} = \frac{- 50 \pm 10 985}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- 50 + 10 985}{2 \cdot 5}, v_{2} = \frac{- 50 - 10 985}{2 \cdot 5}

v = \frac{- 50 + 10 985}{2 \cdot 5} : - 5 + 985

v = \frac{- 50 - 10 985}{2 \cdot 5} : - 5 - 985

The solutions to the quadratic equation are:

v = - 5 + 985, v = - 5 - 985

- 3 (- c - 12) = - 3 c - 12

x^{2} = 21

- 8 < 2 - 5 n \leq 11

\frac{1}{3} \cdot \frac{1}{9}

b^{2} + 9 b + 18

What are the solutions to the equation 0.05v^2+0.5v=48 ?
The solutions to the equation 0.05v^2+0.5v=48 are v=-5+sqrt(985),v=-5-sqrt(985)
Find the zeros of 0.05v^2+0.5v=48
The zeros of 0.05v^2+0.5v=48 are v=-5+sqrt(985),v=-5-sqrt(985)