What are the solutions to the equation (x+4)(x-5)=0 ?

The solutions to the equation (x+4)(x-5)=0 are x=-4,x=5

Find the zeros of (x+4)(x-5)=0

The zeros of (x+4)(x-5)=0 are x=-4,x=5

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(x + 4) (x - 5) = 0

x = - 4, x = 5

Solution steps

(x + 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x - 5 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = - 4, x = 5

11 - w < 12

50 x^{7} y^{7} \cdot 6 x y^{4}

r^{2} + 6 r - 44 = - 4

2 x^{2} - 9 x + 9

\frac{x + 5}{1 - 2 x} < 0

What are the solutions to the equation (x+4)(x-5)=0 ?
The solutions to the equation (x+4)(x-5)=0 are x=-4,x=5
Find the zeros of (x+4)(x-5)=0
The zeros of (x+4)(x-5)=0 are x=-4,x=5