What are the solutions to the equation r^2+6r-44=-4 ?

The solutions to the equation r^2+6r-44=-4 are r=4,r=-10

Find the zeros of r^2+6r-44=-4

The zeros of r^2+6r-44=-4 are r=4,r=-10

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r^{2} + 6 r - 44 = - 4

r = 4, r = - 10

Solution steps

r^{2} + 6 r - 44 = - 4

Move

4

to the left side

r^{2} + 6 r - 40 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 40) = 14

r_{1, 2} = \frac{- 6 \pm 14}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 6 + 14}{2 \cdot 1}, r_{2} = \frac{- 6 - 14}{2 \cdot 1}

r = \frac{- 6 + 14}{2 \cdot 1} : 4

r = \frac{- 6 - 14}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

r = 4, r = - 10

2 x^{2} - 9 x + 9

\frac{x + 5}{1 - 2 x} < 0

8 x^{2} = 5 x

4 x^{2} - 5 x = 2

2 x^{2} + 7 x - 5 > 10

What are the solutions to the equation r^2+6r-44=-4 ?
The solutions to the equation r^2+6r-44=-4 are r=4,r=-10
Find the zeros of r^2+6r-44=-4
The zeros of r^2+6r-44=-4 are r=4,r=-10